C Program to Find Transpose of a Matrix using Pointers

C program to find transpose of a matrix : Transpose of a mxn (3x3) matrix can be obtained by interchanging the rows and columns in C using pointers and dynamic memory allocation.

For Example: Consider a 3x3 matrix

1 2 3
4 5 6
7 8 9

Transpose of matrix is
1 4 7
2 5 8
3 6 9

C program to find transpose of a matrix

#include<stdio.h>
#include<stdlib.h>
int main()
{
	int matrix[10][10],i,j,r,c;
	printf("\n How many rows and columns in the matrix:- ");
	scanf(" %d %d",&r,&c);
	printf("\n Enter the elements:- ");
	for(i=0;i<r;i++)
	for(j=0;j<c;j++) 
	{
	scanf("%d",&matrix[i][j]);
	}
	printf("\n The transpose of matrix is:- \n");
	for(i=0;i<c;i++)
	{
	for(j=0;j<r;j++)
		printf("%5d",matrix[j][i]);
	printf("\n");
	}
	return 0; 
}
/* Output of above code:- 
 How many rows and columns in the matrix:- 3 3 
 Enter the elements:- 
1 2 3 
4 5 6
7 8 9
 The transpose of matrix is:- 
 1 4 7
 2 5 8
 3 6 9
*/

Output of C programming code:

C program to find transpose of a matrix using dynamic memory allocation

#include<stdio.h>
#include<stdlib.h>
int main()
{
	int *transpose,i,j,r,c; //declaring pointers
	printf("\n How many rows and columns in the matrix:- ");
	scanf(" %d %d",&r,&c);
//allocating memory by using dynamic memory allocation
	transpose=(int*)calloc(r*c,sizeof(int));
	printf("\n Enter the elements:- ");
	for(i=0;i<r;i++)
	for(j=0;j<c;j++) 
	{
	scanf("%d",transpose+(i*c+j)*sizeof(int));
	}
// You can achieve the same result by using pointer concept
	printf("\n The transpose of matrix is:- \n");
	for(i=0;i<c;i++)
	{
	for(j=0;j<r;j++)
		printf("%5d",*(transpose+(j*c+i)*sizeof(int)));
	printf("\n");
	}
	return 0;
}
/* Output of above code:- 
 How many rows and columns in the matrix:- 3 3 
 Enter the elements:- 
1 2 3 
4 5 6
7 8 9
 The transpose of matrix is:- 
 1 4 7
 2 5 8
 3 6 9
*/

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